本文实例讲述了Python实现的递归神经网络。分享给大家供大家参考，具体如下：
# Recurrent Neural Networks
import copy, numpy as np
np.random.seed(0)
# compute sigmoid nonlinearity
def sigmoid(x):
output = 1/(1+np.exp(-x))
return output
# convert output of sigmoid function to its derivative
def sigmoid_output_to_derivative(output):
return output*(1-output)
# training dataset generation
int2binary = {}
binary_dim = 8
largest_number = pow(2,binary_dim)
binary = np.unpackbits(
np.array([range(largest_number)],dtype=np.uint8).T,axis=1)
for i in range(largest_number):
int2binary[i] = binary[i]
# input variables
alpha = 0.1
input_dim = 2
hidden_dim = 16
output_dim = 1
# initialize neural network weights
synapse_0 = 2*np.random.random((input_dim,hidden_dim)) - 1
synapse_1 = 2*np.random.random((hidden_dim,output_dim)) - 1
synapse_h = 2*np.random.random((hidden_dim,hidden_dim)) - 1
synapse_0_update = np.zeros_like(synapse_0)
synapse_1_update = np.zeros_like(synapse_1)
synapse_h_update = np.zeros_like(synapse_h)
# training logic
for j in range(10000):
# generate a simple addition problem (a + b = c)
a_int = np.random.randint(largest_number/2) # int version
a = int2binary[a_int] # binary encoding
b_int = np.random.randint(largest_number/2) # int version
b = int2binary[b_int] # binary encoding
# true answer
c_int = a_int + b_int
c = int2binary[c_int]
# where we'll store our best guess (binary encoded)
d = np.zeros_like(c)
overallError = 0
layer_2_deltas = list()
layer_1_values = list()
layer_1_values.append(np.zeros(hidden_dim))
# moving along the positions in the binary encoding
for position in range(binary_dim):
# generate input and output
X = np.array([[a[binary_dim - position - 1],b[binary_dim - position - 1]]])
y = np.array([[c[binary_dim - position - 1]]]).T
# hidden layer (input ~+ prev_hidden)
layer_1 = sigmoid(np.dot(X,synapse_0) + np.dot(layer_1_values[-1],synapse_h))
# output layer (new binary representation)
layer_2 = sigmoid(np.dot(layer_1,synapse_1))
# did we miss"Error:" + str(overallError))
print("Pred:" + str(d))
print("True:" + str(c))
out = 0
for index,x in enumerate(reversed(d)):
out += x*pow(2,index)
print(str(a_int) + " + " + str(b_int) + " = " + str(out))
print("------------")
运行输出：
Error:[ 3.45638663] Pred:[0 0 0 0 0 0 0 1] True:[0 1 0 0 0 1 0 1] 9 + 60 = 1 ------------ Error:[ 3.63389116] Pred:[1 1 1 1 1 1 1 1] True:[0 0 1 1 1 1 1 1] 28 + 35 = 255 ------------ Error:[ 3.91366595] Pred:[0 1 0 0 1 0 0 0] True:[1 0 1 0 0 0 0 0] 116 + 44 = 72 ------------ Error:[ 3.72191702] Pred:[1 1 0 1 1 1 1 1] True:[0 1 0 0 1 1 0 1] 4 + 73 = 223 ------------ Error:[ 3.5852713] Pred:[0 0 0 0 1 0 0 0] True:[0 1 0 1 0 0 1 0] 71 + 11 = 8 ------------ Error:[ 2.53352328] Pred:[1 0 1 0 0 0 1 0] True:[1 1 0 0 0 0 1 0] 81 + 113 = 162 ------------ Error:[ 0.57691441] Pred:[0 1 0 1 0 0 0 1] True:[0 1 0 1 0 0 0 1] 81 + 0 = 81 ------------ Error:[ 1.42589952] Pred:[1 0 0 0 0 0 0 1] True:[1 0 0 0 0 0 0 1] 4 + 125 = 129 ------------ Error:[ 0.47477457] Pred:[0 0 1 1 1 0 0 0] True:[0 0 1 1 1 0 0 0] 39 + 17 = 56 ------------ Error:[ 0.21595037] Pred:[0 0 0 0 1 1 1 0] True:[0 0 0 0 1 1 1 0] 11 + 3 = 14 ------------
英文原文：https://iamtrask.github.io/2015/11/15/anyone-can-code-lstm/
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