其实本来是要reverse一下list的，就去查了一下list[::-1]是什么意思，发现还有很多要注意的地方，所以就记一下。
主要是参照https://docs.python.org/3/library/stdtypes.html"htmlcode">
> a = [1, 2, 3] > a[::-1] [3, 2, 1] > a = (1, 2, 3) > a[::-1] (3, 2, 1) > a = range(3) > a[::-1] range(2, -1, -1)
range中参数是range(start, stop[, step])
initialize a list
s * n表示的是n shallow copies of s concatenated
注意是浅拷贝哦，所以会有如下情况
> lists = [[]] * 3 > lists [[], [], []] > lists[0].append(3) > lists [[3], [3], [3]]
如果元素不是对象的话就没关系
> lists = [0] * 3 > lists [0, 0, 0] > lists[0] = 1 > lists [1, 0, 0]
正确的初始化嵌套list的方法应该是
> lists = [[] for i in range(3)] > lists[0].append(3) > lists[1].append(5) > lists[2].append(7) > lists [[3], [5], [7]]
concatenation pitfall
(感觉还是英文说的清楚些，这一点跟Java是一样的)
Concatenating immutable sequences always results in a new object. This means that building up a sequence by repeated concatenation will have a quadratic runtime cost in the total sequence length. To get a linear runtime cost, you must switch to one of the alternatives below: