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Vue 401配合Vuex防止多次弹框的案例

1.安装Vuex

npm install vuex --save

2. 新建store目录结构

Vue 401配合Vuex防止多次弹框的案例

3. 编辑store.js

import Vuex from 'vuex'
import Vue from 'vue'
import defaultState from './state/state'
import mutations from './mutations/mutations'
import getters from './getters/getters'
import actions from './actions/actions'
 
Vue.use(Vuex)
 
// 开发环境
const isDev = process.env.NODE_ENV === 'development'
 
export default new Vuex.Store({
 strict: isDev, // 开发环境中使用严格模式,防止给Vuex的状态对象直接赋值
 state: defaultState,
 mutations,
 getters,
 actions
})

4. 编辑state.js

export default {
 tokenStatus: true, // token状态
}

5. 编辑mutations.js

export default {
 updateTokenStatus (state, bool) {
  state.tokenStatus = bool
 }
}

PS: getters用于计算属性,actions用于异步操作(暂无使用)

6. 挂载到vue根目录下,编辑main.js

import store from './store/store'
 
new Vue({
 store,
 router,
 render: h => h(App)
}).$mount('#app')

7. login 登录时,改变state.tokenStatus的值

import { mapMutations } from 'vuex' 
methods: {
  // 声明Vuex的mutations的方法
  ...mapMutations(['updateTokenStatus']),
  // 登录方法
  login () {
    ......
    // 改变Vuex.state.tokenStatus的值
    this.updateTokenStatus(true)
  }
}

8. 配置axios的错误判断

// 初始化用户信息
  initUserInfo () {
   const p1 = this.$api.user.getUserInfo()
   p1.then(result => {
    this.data = result
    this.isEdit = false
    this.firstLoading = false
   }).catch(reason => {
    this.firstLoading = false
    this.isEdit = false
    // 目前后端是通过code为-1,返回错误信息
    if (parseInt(reason.code) === -1) {
     this.$alert(reason.message, '提示', { type: 'error' })
    }
   })
  },

9. 拦截响应, 处理401,返回自定义错误

import router from '../../router'
import axios from 'axios'
import localStorage from 'localStorage'
import { MessageBox } from 'element-ui'
import store from '../../store/store'
 
// http response 拦截器
axios.interceptors.response.use(
 response => {
  return response
 },
 error => {
  if (error.response) {
   if (error.response.status === 401) {
    switch (error.response.status) {
     case 401:
      const route = localStorage.getItem('vip_entrance')
      router.replace({
       path: route,
       query: { redirect: router.currentRoute.fullPath }
      })
      if (store.state.tokenStatus) {
       // 饿了么框架弹框
       MessageBox.alert('登录超时!', '提示', { type: 'error' })
       // 修改tokenStatus状态,防止多次点击
       store.commit('updateTokenStatus', false)
      }
      const data = {
       code: 1
      }
      return Promise.reject(data)
    }
   }
  }
  return Promise.reject(error.response.data)
 }
)

补充知识:vue 配置vuex在严格模式下出现是问题

我就废话不多说了,大家还是直接看代码吧~

需要关闭严格模式,不然会报错

import Vue from "vue";
import Vuex from "vuex";
import createPersistedState from "vuex-persistedstate";
import * as Cookies from "js-cookie";
import user from "./modules/user";
import myCen from "./modules/myCen";
import registered from "./modules/registered";
Vue.use(Vuex);

export default new Vuex.Store({
 strict: false, //关闭严格模式
 modules: {
  user,
  myCen,
  registered
 },
 // 持久化储存
 plugins: [ 
  createPersistedState({
   storage: {
    getItem: key => Cookies.get(key),
    setItem: (key, value) => Cookies.set(key, value, { expires: 7 }),
    removeItem: key => Cookies.remove(key)
   }
  })
 ]
});

以上这篇Vue 401配合Vuex防止多次弹框的案例就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持。