本文实例讲述了JS实现的字符串数组去重功能。分享给大家供大家参考，具体如下：
这里只考虑最简单字符串的数组去重，暂不考虑，对象，函数，NaN等情况，这种用正则实现起来就吃力不讨好了。
非正则实现：ES6实现
<script>
let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr){
return [...new Set(arr)]
}
console.log(unique(str_arr))
</script>
运行结果：
ES5实现
<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr) {
return arr.filter(function(ele, index, array) {
return array.indexOf(ele) === index
})
}
console.log(unique(str_arr))
</script>
运行结果同上
ES3实现
<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr) {
var obj = {},
array = []
for (var i = 0, len = arr.length; i < len; i++) {
var key = arr[i] + typeof arr[i]
if (!obj[key]) {
obj[key] = true
array.push(arr[i])
}
}
return array
}
console.log(unique(str_arr))
</script>
运行结果同上
用正则实现
<script>
var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"]
function unique(arr) {
return arr.sort().join(",,").
replace(/(,|^)([^,]+)(,,\2)+(,|$)/g, "$1$2$4").
replace(/,,+/g, ",").
replace(/,$/, "").
split(",")
}
console.log(unique(str_arr))
</script>
运行结果：
感兴趣的朋友可以使用在线HTML/CSS/JavaScript代码运行工具：http://tools.jb51.net/code/HtmlJsRun测试上述代码运行效果。
PS：这里再为大家提供几款相关工具供大家参考使用：
在线去除重复项工具：
http://tools.jb51.net/code/quchong
在线文本去重复工具：
http://tools.jb51.net/aideddesign/txt_quchong
更多关于JavaScript相关内容还可查看本站专题：《JavaScript数组操作技巧总结》、《JavaScript字符与字符串操作技巧总结》、《JavaScript遍历算法与技巧总结》、《JavaScript查找算法技巧总结》、《JavaScript数学运算用法总结》、《JavaScript数据结构与算法技巧总结》及《JavaScript错误与调试技巧总结》
希望本文所述对大家JavaScript程序设计有所帮助。